A tower stands vertically on the ground. From a point on the ground, the angle of elevation of the top of the tower is 60^\circ. If the distance from the point to the foot of tower is 27 m, find the height of the tower. (Take \sqrt{3} = 1.7)
- A. 25.65 meters
- B. 45.9 meters ✓
- C. 22.95 meters
- D. 43.2 meters
Correct Answer: B. 45.9 meters
Explanation
Let height be h. \tan(60^\circ) = \frac{h}{27} \Rightarrow h = 27 \times \sqrt{3}. Using \sqrt{3} = 1.7, h = 27 \times 1.7 = 45.9 m.