A bag contains 3 red, 5 blue, and 2 green balls. Two balls are drawn one after another without replacement. Find the probability that both balls are blue.
- A. \frac{2}{9} ✓
- B. \frac{1}{6}
- C. \frac{2}{5}
- D. \frac{5}{18}
Correct Answer: A. \frac{2}{9}
Explanation
Total balls = 3 + 5 + 2 = 10. Probability of first blue = \frac{5}{10}. Probability of second blue = \frac{4}{9}. Total probability = \frac{5}{10} \times \frac{4}{9} = \frac{20}{90} = \frac{2}{9}.