A scout starts walking in the forest starting from Point A towards the east for 5 m, then turns 60^\circ left at Point P and walks for 15 m to reach Point C. She then turns 60^\circ left and walks for 15 m to reach Point D. What is the shortest distance the scout can take to reach Point P again from Point D?

  1. A. 2\sqrt{5} m
  2. B. 20 m
  3. C. 5\sqrt{2} m
  4. D. 15 m ✓

Correct Answer: D. 15 m

Explanation

The path from P to C to D forms two sides of an equilateral triangle (since the turns are 60^\circ and distances are equal at 15 m). Thus, the distance from D back to P is the third side of the equilateral triangle, which is 15 m.

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