What is the magnitude (in radian) of the interior angle of a regular pentagon?
- A. \frac{\pi}{5}
- B. \frac{2\pi}{5}
- C. \frac{3\pi}{5} ✓
- D. \frac{4\pi}{5}
Correct Answer: C. \frac{3\pi}{5}
Explanation
The formula for the interior angle of a regular n-gon is \frac{(n-2)\pi}{n} radians. For a pentagon, n=5, so the interior angle is \frac{(5-2)\pi}{5} = \frac{3\pi}{5} radians.
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