ABCD is a cyclic quadrilateral. The bisectors of the angles A, B, C and D cut the circle at P, Q, R and S respectively. What is \angle PQR+\angle RSP equal to?
- A. 90^{\circ}
- B. 135^{\circ}
- C. 180^{\circ} ✓
- D. 270^{\circ}
Correct Answer: C. 180^{\circ}
Explanation
The points P, Q, R, and S lie on the circle, making PQRS a cyclic quadrilateral itself. In any cyclic quadrilateral, the sum of opposite angles is always 180^\circ. Therefore, \angle PQR + \angle RSP = 180^\circ.
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