How many pairs of (x, y) can be chosen from the set \{2,3,6,8,9\} such that \frac{x}{y}+\frac{y}{x}=2, where x \neq y?

Explanation

The given equation simplifies to x^2+y^2=2xy, which implies (x-y)^2=0 \implies x=y. Since the condition strictly requires x \neq y, zero pairs are possible.

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