If the sum as well as the product of the roots of the equation px^{2}-6x+q=0 is 6, then what is (p+q) equal to?

Explanation

The sum of the roots is \frac{-(-6)}{p} = \frac{6}{p}. Since this equals 6, we get p = 1. The product of the roots is \frac{q}{p} = 6. Substituting p = 1 gives q = 6. Hence, p + q = 1 + 6 = 7.

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