Walking at \frac{4}{5}\text{th} of his usual speed, a man is 12\text{ minutes} late for his office. What is the usual time taken by him to cover that distance?

Explanation

Since speed and time are inversely proportional, reducing speed to \frac{4}{5} increases the time taken to \frac{5}{4} of the usual time (t). The extra time is \frac{1}{4}t = 12\text{ minutes}, which means t = 48\text{ minutes}.

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