The ratio of the radius of base to the height of a cylinder is 2:3. If the volume of the cylinder is 1617\text{ cm}^3, then what is the curved surface area of the cylinder? (Take \pi=\frac{22}{7})

  1. A. 242\text{ cm}^2
  2. B. 385\text{ cm}^2
  3. C. 462\text{ cm}^2
  4. D. 770\text{ cm}^2

Correct Answer: C. 462\text{ cm}^2

Explanation

Let radius r = 2x and height h = 3x. Volume = \pi(2x)^2(3x) = 12\pi x^3 = 1617. Thus, 12 \times \frac{22}{7} \times x^3 = 1617 \implies x^3 = \frac{1617 \times 7}{264} = \frac{343}{8} \implies x = 1.5. Then r = 7, h = 10.5. Curved surface area = 2\pi rh = 2 \times \frac{22}{7} \times 7 \times 10.5 = 462\text{ cm}^2.

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