A metal solid cube of side 22\text{ cm} is melted to make a cone of height 21\text{ cm}. What is the radius of the base of the cone? (Take \pi=\frac{22}{7})

Explanation

Volume is conserved: 22^3 = \frac{1}{3}\pi r^2 h \implies 10648 = \frac{1}{3} \times \frac{22}{7} \times r^2 \times 21 = 22r^2. Solving for r^2 gives r^2 = \frac{10648}{22} = 484, so r = 22\text{ cm}.

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