A hollow spherical shell is made up of a metal of density 3\text{ g/cm}^3. If the internal and external radii are 5\text{ cm} and 6\text{ cm} respectively, then what is the mass of the shell? (Take \pi=\frac{22}{7})

Explanation

Volume of metal = \frac{4}{3}\pi(R^3-r^3) = \frac{4}{3} \times \frac{22}{7} \times (6^3 - 5^3) = \frac{88}{21}(216 - 125) = \frac{88}{21}(91) = \frac{1144}{3}\text{ cm}^3. Mass = Volume \times Density = \frac{1144}{3} \times 3 = 1144\text{ g}.

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