A wire is in the form of a circle of radius 70\text{ cm}. If it is bent in the form of a rhombus, then what is its side length? (Take \pi=\frac{22}{7})

Explanation

Length of the wire is the circumference of the circle = 2\pi r = 2 \times \frac{22}{7} \times 70 = 440\text{ cm}. The perimeter of the rhombus must also be 440\text{ cm}. Perimeter = 4a = 440 \implies a = 110\text{ cm}.

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