ABC is a triangle right angled at A and AD is perpendicular to BC. If BD=8\text{ cm} and DC=12.5\text{ cm}, then what is AD equal to?

Explanation

In a right-angled triangle, the altitude drawn to the hypotenuse divides it such that AD^2 = BD \times DC. Thus, AD^2 = 8 \times 12.5 = 100 \implies AD = 10\text{ cm}.

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