If the perimeter of a right-angled triangle is 30~\text{cm} and the hypotenuse is 13~\text{cm}, then what is the area of the triangle?

  1. A. 24~\text{cm}^2
  2. B. 27~\text{cm}^2
  3. C. 30~\text{cm}^2
  4. D. 36~\text{cm}^2

Correct Answer: C. 30~\text{cm}^2

Explanation

Let the legs be a and b. We know a+b+13 = 30, so a+b=17. By Pythagoras, a^2+b^2=13^2=169. Squaring the first equation: (a+b)^2 = a^2+b^2+2ab \implies 289 = 169 + 2ab \implies 2ab = 120. The area is \frac{1}{2}ab = 30~\text{cm}^2.

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