If \log_{10}x+\log_{10}x^{2}=2\log_{10}x+1, then what is the value of x?

Explanation

Using properties of logarithms, \log_{10}x + 2\log_{10}x = 2\log_{10}x + 1. This simplifies to \log_{10}x = 1, which gives x = 10^1 = 10.

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