Let work done by (3n-1) men in (2n+1) days be x and work done by (3n+1) men in (4n-3) days be y. If x:y=6:11, then what is the value of n?

Explanation

We have \frac{x}{y} = \frac{(3n-1)(2n+1)}{(3n+1)(4n-3)} = \frac{6}{11}. Testing the options, for n=7, the LHS becomes \frac{(20)(15)}{(22)(25)} = \frac{300}{550} = \frac{6}{11}, matching the RHS.

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