If 2x-3y-7=0, then what is the value of 8x^{3}-36x^{2}y+54xy^{2}-27y^{3}-340?

Explanation

The given expression features the expansion of (2x-3y)^3. Specifically, (2x-3y)^3 = 8x^3 - 36x^2y + 54xy^2 - 27y^3. Since 2x-3y = 7, we substitute this to get 7^3 - 340 = 343 - 340 = 3.

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