A person rode one-third of a journey at 60 km/hr, one-third at 50 km/hr and the rest at 40 km/hr. Had the person ridden half of the journey at 60 km/hr and the rest at 40 km/hr, he would have taken 4 minutes longer to complete the journey. What distance did the person ride?

Explanation

Let total distance be D. Time in first case = \frac{D}{180} + \frac{D}{150} + \frac{D}{120} = \frac{37D}{1800}. Time in second case = \frac{D}{120} + \frac{D}{80} = \frac{5D}{240} = \frac{37.5D}{1800}. The difference is \frac{0.5D}{1800} = \frac{D}{3600} hours. Equating to 4 minutes (\frac{1}{15} hour), we get \frac{D}{3600} = \frac{1}{15} \implies D = 240 km.

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