A solid rod consists of a cylinder of height 20 cm and radius 7 cm. It is surmounted by another solid cylinder of height 10 cm and radius 3.5 cm. If 1 cubic metre of rod weighs 10000 kg, what is the mass of the rod? (take \pi=\frac{22}{7})

Explanation

Volume of lower cylinder = \frac{22}{7} \times 7^2 \times 20 = 3080\text{ cm}^3. Volume of upper cylinder = \frac{22}{7} \times 3.5^2 \times 10 = 385\text{ cm}^3. Total volume = 3465\text{ cm}^3 = 3465 \times 10^{-6}\text{ m}^3. Mass = 3465 \times 10^{-6} \times 10000 = 34.65\text{ kg}.

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