If x=9999, then what is the value of the following? \frac{4x^3-x}{(2x+1)(6x-3)}

Explanation

Simplify the expression: \frac{x(4x^2-1)}{3(2x+1)(2x-1)} = \frac{x(2x-1)(2x+1)}{3(2x-1)(2x+1)} = \frac{x}{3}. Substituting x=9999, we get \frac{9999}{3} = 3333.

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