Let p=2^{2n+2}+m and q=2^{4n}-m (where n is even natural number). What should be the <strong>LEAST</strong> value of m such that p as well as q is divisible by 5?

Explanation

Since n is an even natural number, let n=2. Then p = 2^6 + m = 64 + m and q = 2^8 - m = 256 - m. For both to be divisible by 5, the units digit must be 0 or 5. The smallest option that works is m=1, giving p=65 and q=255.

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