If A, B, C, D are the angles of a cyclic quadrilateral, then what is the value of the following? \sin\left(\frac{A+C}{2}\right)+\sin\left(\frac{B+D}{2}\right)

Explanation

In a cyclic quadrilateral, the sum of opposite angles is 180^\circ. Thus, A+C = 180^\circ and B+D = 180^\circ. Substituting these values gives \sin(90^\circ) + \sin(90^\circ) = 1 + 1 = 2.

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