A circle of radius 25 cm has a chord of length 48 cm. What is the length of the perpendicular drawn from the centre of the circle to the chord?

Explanation

The perpendicular from the center bisects the chord into two 24 cm segments. Using Pythagoras theorem, the distance d = \sqrt{25^2 - 24^2} = \sqrt{625 - 576} = \sqrt{49} = 7 cm.

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