ABCD is a parallelogram with AB=15 cm and AD=8 cm. If \theta is the acute angle between AB and AD, then what is the area of the parallelogram in square cm?
- A. 60 \sin \theta
- B. 120 \sin \theta ✓
- C. 60 \cos \theta
- D. 120 \cos \theta
Correct Answer: B. 120 \sin \theta
Explanation
The area of a parallelogram is given by the product of its adjacent sides and the sine of the included angle. Area = AB \times AD \times \sin \theta = 15 \times 8 \times \sin \theta = 120 \sin \theta.
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