What is \frac{1}{x(x-y)(x-z)}+\frac{1}{y(y-z)(y-x)}+\frac{1}{z(z-x)(z-y)} equal to?

  1. A. 0
  2. B. 1
  3. C. \frac{1}{xyz}
  4. D. -\frac{1}{xyz}

Correct Answer: C. \frac{1}{xyz}

Explanation

Taking the LCM as xyz(x-y)(y-z)(z-x), the numerator simplifies to -yz(y-z) - zx(z-x) - xy(x-y), which equals (x-y)(y-z)(z-x). Dividing this by the denominator leaves \frac{1}{xyz}.

Related questions on Algebra

Practice more CDS Elementary Mathematics questions