A person X starts from a place A and another person Y starts simultaneously from another place B which is d km away from A. They walk in the same direction. X walks at an average speed of u km/hr and Y walks at an average speed of v km/hr. How far will X have walked before he overtakes Y?
- A. \frac{ud}{(u-v)} ✓
- B. \frac{vd}{(u-v)}
- C. \frac{(ud-vd)}{(u-v)}
- D. \frac{(ud+vd)}{(u+v)}
Correct Answer: A. \frac{ud}{(u-v)}
Explanation
Relative speed of X with respect to Y is (u-v)\text{ km/hr}. The time taken to cover the initial gap d is t = \frac{d}{u-v} hours. Distance covered by X in this time is u \times t = \frac{ud}{u-v}.
Related questions on Arithmetic
- What is the remainder when (17^{25} + 19^{25}) is divided by 18?
- A bottle contains spirit and water in the ratio 1:4 and another identical bottle contains spirit and water in the ratio 4:1. In what rat...
- Let P = 5^5 \times 15^{15} \times 25^{25} \times 35^{35} and Q = 10^{10} \times 20^{20} \times 30^{30} \times 40^{40}. What is the numbe...
- Two students X and Y appeared in a test. The score of X is 20 more than that of Y. If the score of X is 75% of the sum of the scores of X an...
- Question: The product of a natural number N and the number M written by the same digits of N in the reverse order is 252. What is the number...