Three resistors of resistances 11~\Omega, 22~\Omega and 33~\Omega are connected in parallel. Their equivalent resistance is equal to
- A. 66~\Omega
- B. 22~\Omega
- C. 12~\Omega
- D. 6~\Omega ✓
Correct Answer: D. 6~\Omega
Explanation
For resistors in parallel, \frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}. Here, \frac{1}{11} + \frac{1}{22} + \frac{1}{33} = \frac{6}{66} + \frac{3}{66} + \frac{2}{66} = \frac{11}{66} = \frac{1}{6}. Thus, R_{eq} = 6~\Omega.
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