A car moving with a speed of 12~m/s is subjected to brakes which produces a deceleration of 6~m/s^2. The car takes 2s to stop after the application of brakes. What is the distance covered by the car after the application of brakes?
- A. 12 m ✓
- B. 24 m
- C. 36 m
- D. 48 m
Correct Answer: A. 12 m
Explanation
Using the equation of motion s = ut + \frac{1}{2}at^2, where u = 12~m/s, a = -6~m/s^2, and t = 2~s. The distance is s = 12(2) - 0.5(6)(4) = 24 - 12 = 12 m.
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