What is the <strong>LARGEST</strong> number which divides both 2^{35}-1 and 2^{91}-1?

Explanation

Using the property \text{HCF}(a^m-1, a^n-1) = a^{\text{HCF}(m,n)} - 1. Since \text{HCF}(35, 91) = 7, the largest dividing number is 2^7 - 1 = 127.

Related questions on Arithmetic

• What is the remainder when (17^{25} + 19^{25}) is divided by 18?
• A bottle contains spirit and water in the ratio 1:4 and another identical bottle contains spirit and water in the ratio 4:1. In what rat...
• Let P = 5^5 \times 15^{15} \times 25^{25} \times 35^{35} and Q = 10^{10} \times 20^{20} \times 30^{30} \times 40^{40}. What is the numbe...
• Two students X and Y appeared in a test. The score of X is 20 more than that of Y. If the score of X is 75% of the sum of the scores of X an...
• Question: The product of a natural number N and the number M written by the same digits of N in the reverse order is 252. What is the number...