A can do a certain work at twice the speed of B. Further, B can do the same work at 1.5 times the speed of C. <strong>ALL</strong> of them together can finish the work in 12 days. In how many days can C <strong>ALONE</strong> finish the work?
- A. 36 days
- B. 45 days
- C. 60 days
- D. 66 days ✓
Correct Answer: D. 66 days
Explanation
Let C's efficiency be 2 units/day. Then B's is 2 \times 1.5 = 3, and A's is 3 \times 2 = 6. Total efficiency = 6+3+2 = 11. Total work = 11 \times 12 = 132. Time for C alone = 132 / 2 = 66 days.
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