Let x be the area of a square inscribed in a circle of radius r and y be the area of an equilateral triangle inscribed in the same circle. Which one of the following is correct?

  1. A. 9x^{2}=16y^{2}
  2. B. 27x^{2}=64y^{2}
  3. C. 36x^{2}=49y^{2}
  4. D. 16x^{2}=21y^{2}

Correct Answer: B. 27x^{2}=64y^{2}

Explanation

For the inscribed square, the diagonal is 2r. Side a = r\sqrt{2}, so area x = a^2 = 2r^2. For the inscribed equilateral triangle, the circumradius r = \frac{s}{\sqrt{3}}, so side s = r\sqrt{3}. Area y = \frac{\sqrt{3}}{4}s^2 = \frac{3\sqrt{3}}{4}r^2. The ratio \frac{x}{y} = \frac{2r^2}{\frac{3\sqrt{3}}{4}r^2} = \frac{8}{3\sqrt{3}}. Squaring both sides: \frac{x^2}{y^2} = \frac{64}{27}, which gives 27x^2 = 64y^2.

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