If the length of a rectangle is increased by 66\frac{2}{3}\%, then by what percent should the width of the rectangle be decreased in order to maintain the same area?

Explanation

An increase of 66\frac{2}{3}\% is equivalent to multiplying by 1 + \frac{2}{3} = \frac{5}{3}. To keep the area constant (L \times W), the width must be multiplied by the reciprocal, \frac{3}{5}. A multiplier of \frac{3}{5} represents a decrease of 1 - \frac{3}{5} = \frac{2}{5}, which is 40\%.

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