Let X=\{x|x=2+4k, \text{ where } k=0,1,2,3,...24\}. Let S be a subset of X such that the sum of no two elements of S is 100. What is the <strong>MAXIMUM</strong> possible number of elements in S?

  1. A. 10
  2. B. 11
  3. C. 12
  4. D. 13

Correct Answer: D. 13

Explanation

Set X has 25 elements: \{2, 6, 10, ..., 98\}. There are 12 disjoint pairs summing to 100 (e.g., 2+98, 6+94) and the standalone element 50. To maximize subset S without forming a pair that sums to 100, select exactly one element from each of the 12 pairs, plus the element 50. Maximum elements = 12 + 1 = 13.

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