What is the radius of the circle?
Consider the following for the next three (03) items that follow:<br>In the triangle ABC, AB=6 cm, BC=8 cm and AC=10 cm. The perpendicular dropped from B meets the side AC at D. A circle of radius BD (with centre B) cuts AB and BC at P and Q respectively as shown in the figure.
- A. 5 cm
- B. 4.8 cm ✓
- C. 4.4 cm
- D. 4 cm
Correct Answer: B. 4.8 cm
Explanation
The radius of the circle is BD. The length of the altitude to the hypotenuse in a right triangle is \frac{\text{base} \times \text{perpendicular}}{\text{hypotenuse}} = \frac{6 \times 8}{10} = 4.8 cm.
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