A man walks at an average speed of 3~km/hr from his home and reaches office 40 minutes early. If he walks at an average speed of 2~km/hr, he would reach office 40 minutes late. What is the distance between his home and office?
- A. 6 km
- B. 8 km ✓
- C. 10 km
- D. 12 km
Correct Answer: B. 8 km
Explanation
Let the distance be d. The difference in time taken at the two speeds is 40 - (-40) = 80 minutes, which is \frac{4}{3} hours. Therefore, \frac{d}{2} - \frac{d}{3} = \frac{4}{3} \implies \frac{d}{6} = \frac{4}{3}, yielding d = 8 km.
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