What is the height of the cone?
Consider the following for the next two (02) items that follow : A right conical cap just covers two spheres placed one above the other on a table such that it touches both the spheres. Let r be the radius of the smaller sphere and R be the radius of the bigger sphere. Let 2\theta be the vertical angle of the cone.
- A. \frac{2r^{2}}{R-r}
- B. \frac{2R^{2}}{R-r} ✓
- C. \frac{2(r^{2}+R^{2})}{R-r}
- D. \frac{r^{2}+R^{2}}{R-r}
Correct Answer: B. \frac{2R^{2}}{R-r}
Explanation
Let the cone's vertex distance to the large sphere's center be x. Since \sin \theta = \frac{R}{x} and the distance ratio gives \sin \theta = \frac{R-r}{R+r}, we find x = \frac{R(R+r)}{R-r}. The cone's total height is from vertex to table, x + R = R\left(\frac{R+r}{R-r}\right) + R = \frac{2R^2}{R-r}.
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