What is the median (approximate value) of the distribution?

Consider the following for the next two (02) items that follow : A grouped frequency distribution is given below : <table> <thead><tr><th>Weekly wages in Rupees (₹)</th><th>Numbers of workers</th></tr></thead> <tbody> <tr><td>2050–2550</td><td>5</td></tr> <tr><td>2550–3050</td><td>10</td></tr> <tr><td>3050–3550</td><td>k</td></tr> <tr><td>3550–4050</td><td>8</td></tr> <tr><td>4050–4550</td><td>2</td></tr> <tr><td>4550–5050</td><td>10</td></tr> </tbody> </table>

  1. A. 3,263
  2. B. 3,383
  3. C. 3,413
  4. D. 3,483

Correct Answer: B. 3,383

Explanation

With k=15, total frequency N=50, so N/2 = 25. The cumulative frequency just before the median class is 15. The median class is 3050–3550. Median = 3050 + \frac{25-15}{15} \times 500 = 3050 + 333.33 = 3383.33.

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