What is the radius of the sphere passing through the corners of the cuboid with edges 8 cm, 12 cm and 24 cm?

Explanation

The diameter of the circumscribing sphere is equal to the body diagonal of the cuboid. Diagonal = \sqrt{8^2 + 12^2 + 24^2} = \sqrt{64 + 144 + 576} = \sqrt{784} = 28 cm. The radius is 28 / 2 = 14 cm.

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