Question: Is (a-b+c) \gt (a+b-c), where a, b and c are real numbers?<br>Statement-I:<br>b is negative.<br>Statement-II:<br>c is negative.
Consider the following for the next ten (10) items that follow :<br>Mark option (a) if the question can be answered by using one of the statements alone, but cannot be answered using the other statement alone.<br>Mark option (b) if the question can be answered by using either statement alone.<br>Mark option (c) if the question can be answered by using both the statements together, but cannot be answered using either statement alone.<br>Mark option (d) if the question cannot be answered even by using both the statements together.
- A. The question can be answered by using one of the statements alone, but cannot be answered using the other statement alone
- B. The question can be answered by using either statement alone
- C. The question can be answered by using both the statements together, but cannot be answered using either statement alone
- D. The question cannot be answered even by using both the statements together ✓
Correct Answer: D. The question cannot be answered even by using both the statements together
Explanation
The inequality (a-b+c) \gt (a+b-c) simplifies to 2c \gt 2b, or c \gt b. Statement-I says b \lt 0. Statement-II says c \lt 0. Even using both statements together, we only know both are negative, but we cannot determine if c \gt b.
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