What is the area of the square?

Consider the following for the next three (03) items that follow:<br>A triangle CEF is drawn inside a square ABCD as shown in the figure given below. Given: CF=8 cm, EF=6 cm and CE=10 cm.

  1. A. \frac{512}{17} square cm
  2. B. \frac{625}{13} square cm
  3. C. \frac{1024}{17} square cm
  4. D. \frac{1296}{13} square cm

Correct Answer: C. \frac{1024}{17} square cm

Explanation

Let the side of the square be a. Using the Pythagorean theorem in the three right triangles at the corners, BF = \sqrt{64-a^2} and DE = \sqrt{100-a^2}. The remaining segments on the sides form the third right triangle: (a - \sqrt{100-a^2})^2 + (a - \sqrt{64-a^2})^2 = 6^2. Solving this yields a^2 = \frac{1024}{17}. The area is a^2.

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