What is the area of triangle CDE?
Consider the following for the next three (03) items that follow:<br>A triangle CEF is drawn inside a square ABCD as shown in the figure given below. Given: CF=8 cm, EF=6 cm and CE=10 cm.
- A. \frac{416}{17} square cm ✓
- B. \frac{312}{13} square cm
- C. \frac{208}{17} square cm
- D. \frac{156}{13} square cm
Correct Answer: A. \frac{416}{17} square cm
Explanation
The area of the right-angled triangle CDE is \frac{1}{2} \times CD \times DE. Substituting the side length CD = \frac{32}{\sqrt{17}} and the calculated segment DE = \frac{26}{\sqrt{17}}, the area evaluates to \frac{1}{2} \times \frac{32}{\sqrt{17}} \times \frac{26}{\sqrt{17}} = \frac{416}{17} square cm.
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