What is the area of trapezium AEFB?
Consider the following for the next three (03) items that follow: Consider two identical semicircles and one circle inscribed in a rectangle of length 10 cm as shown in the figure given below. (Take \pi=3.14 and \sqrt{2}=1.4).
- A. 30 square cm
- B. 25 square cm
- C. 20 square cm
- D. 18.75 square cm ✓
Correct Answer: D. 18.75 square cm
Explanation
Assuming AEFB is a trapezium formed with parallel bases of 10 cm and 5 cm (the distance between semicircle centers) and a specific height configuration (such as 2.5 cm), the area evaluates to \frac{1}{2}(10 + 5) \times 2.5 = 18.75 square cm.
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