If the roots of the equation x^2-(k-2)x+(k+1)=0 are equal, then what are the values of k?

Explanation

For equal roots, the discriminant D = 0. D = (k-2)^2 - 4(1)(k+1) = k^2 - 4k + 4 - 4k - 4 = k^2 - 8k = 0. Solving k(k-8) = 0 yields k = 0, 8.

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