Match List-I with List-II and select the answer using the codes given below the Lists:<br> \begin{array}{|l|l|} \hline \textbf{List-I (Symbol of Element)} & \textbf{List-II (Group of Element)} \\ \hline \text{A. Sm} & \text{1. Transition Elements} \\ \hline \text{B. Cs} & \text{2. Alkali Metals} \\ \hline \text{C. Os} & \text{3. Actinoid Elements} \\ \hline \text{D. Np} & \text{4. Lanthanoid Elements} \\ \hline \end{array} <br>Code: A B C D
- A. 4 2 1 3 ✓
- B. 4 1 2 3
- C. 3 1 2 4
- D. 3 2 1 4
Correct Answer: A. 4 2 1 3
Explanation
Samarium (Sm) is a Lanthanoid (A-4). Caesium (Cs) is an Alkali Metal (B-2). Osmium (Os) is a Transition Element (C-1). Neptunium (Np) is an Actinoid Element (D-3).
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