The minimum power required to lift a mass of 50 kg up to a vertical distance of 8 m in 10 s is: (Take g=10~m/s^{2})
- A. 400 W ✓
- B. 40 W
- C. 50 W
- D. 500 W
Correct Answer: A. 400 W
Explanation
Power is Work done per unit time. P = \frac{mgh}{t} = \frac{50 \times 10 \times 8}{10} = 400 W.
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