What is the sum of all the divisors of 256 ?

Explanation

Since 256 = 2^8, its divisors are 2^0, 2^1, \dots, 2^8. The sum forms a geometric progression: \frac{2^{8+1} - 1}{2 - 1} = 2^9 - 1 = 512 - 1 = 511.

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