ABCD is a cyclic quadrilateral. AB and DC are produced to meet at P. Which of the following statements is/are correct ? I. \Delta PAD is similar to \Delta PBC II. \angle PAD + \angle PDA = \angle PBC + \angle PCB Select the answer using the code given below :

Explanation

In a cyclic quadrilateral, an exterior angle equals the opposite interior angle. Thus, in \Delta PAD and \Delta PBC, \angle PAD = \angle PCB and \angle PDA = \angle PBC. Since \angle P is common, \Delta PAD \sim \Delta PBC (I is true). Moreover, the sum of these angles in both triangles is 180^\circ - \angle P, meaning \angle PAD + \angle PDA = \angle PBC + \angle PCB (II is true).

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