What is \frac{(a+b)^2}{(c-a)(c+a+b)} + \frac{(a+b)c}{c^2+bc-a^2-ab} - \frac{a+2b+c}{2(c-a)} equal to?

Explanation

Substituting arbitrary values like a=1, b=2, c=3 into the given expression yields \frac{9}{2\times6} + \frac{9}{9+6-1-2} - \frac{8}{2\times2} = \frac{3}{4} + \frac{3}{4} - 2 = -\frac{1}{2}.

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