What is \frac{\frac{x}{x-y} + \frac{y}{y-z} + \frac{z}{z-x}}{\frac{x+y}{x-y} + \frac{y+z}{y-z} + \frac{z+x}{z-x} + 3} equal to?

  1. A. 1
  2. B. 1/2
  3. C. 1/3
  4. D. 1/4

Correct Answer: B. 1/2

Explanation

Let the numerator be p = \frac{x}{x-y} + \frac{y}{y-z} + \frac{z}{z-x}. By adding the 3 into each term of the denominator as 1 + 1 + 1, it becomes \left(\frac{x+y}{x-y} + 1\right) + \left(\frac{y+z}{y-z} + 1\right) + \left(\frac{z+x}{z-x} + 1\right). This simplifies to \frac{2x}{x-y} + \frac{2y}{y-z} + \frac{2z}{z-x}, which is exactly 2p. Therefore, the ratio is \frac{p}{2p} = \frac{1}{2}.

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