If A=\begin{pmatrix}1&0&0\\ 0&\cos~\theta&\sin~\theta\\ 0&\sin~\theta&-\cos\theta\end{pmatrix}, then which of the following are correct? 1. A+adjA is a null matrix 2. A^{-1}+adjA is a null matrix 3. A-A^{-1} is a null matrix Select the correct answer using the code given below :
- A. 1 and 2 only
- B. 2 and 3 only
- C. 1 and 3 only
- D. 1, 2 and 3 ✓
Correct Answer: D. 1, 2 and 3
Explanation
The determinant of A is -1. Multiplying A by itself yields A^2 = I, meaning A^{-1} = A. Therefore, A - A^{-1} = 0, making Statement 3 true. Also, A^{-1} = \frac{adj A}{|A|} = -adj A. This gives A^{-1} + adj A = 0 (Statement 2) and A + adj A = 0 (Statement 1). All statements are correct.
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